# coding=utf-8
"""
The sum of the squares of the first ten natural numbers is,
1**2 + 2**2 + ... + 10**2 = 385

The square of the sum of the first ten natural numbers is,
(1 + 2 + ... + 10)**2 = 55**2 = 3025

Hence the difference between the sum of the squares of the first ten natural numbers and the square of the sum is 3025 − 385 = 2640.

Find the difference between the sum of the squares of the first one hundred natural numbers and the square of the sum.


翻译:


"""

MAX = 100
sumOfSquares = 0
squaresOfSum = 0

for i in range(1, MAX + 1):
    sumOfSquares += i * i

squaresOfSum = sum(x for x in range(1, MAX + 1)) * sum(x for x in range(1, MAX + 1))

print squaresOfSum - sumOfSquares

# 25164150